18x^2+80x-80=0

Solution for 18x^2+80x-80=0 equation:

18x^2+80x-80=0

a = 18; b = 80; c = -80;
Δ = b2-4ac
Δ = 802-4·18·(-80)
Δ = 12160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12160}=\sqrt{64*190}=\sqrt{64}*\sqrt{190}=8\sqrt{190}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-8\sqrt{190}}{2*18}=\frac{-80-8\sqrt{190}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+8\sqrt{190}}{2*18}=\frac{-80+8\sqrt{190}}{36}
$